1990 American Association season

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The 1990 American Association season was the 83rd in the league's history, and ended with the Omaha Royals winning their first championship since 1978. The Royals would go on to win the Triple-A Classic over the IL's Rochester Red Wings.

Buffalo and Nashville finished the season tied, so a one-game playoff took place September 3 in Buffalo, NY for the East Division title. Nashville won 9-8 in 18 innings, and this result is reflected in the standings below.

Final standings[edit]

Playoff teams in bold.

East Division W L Pct. GB Manager Affiliation
Nashville Sounds 86 61 .585 -- Pete Mackanin Cincinnati Reds
Buffalo Bisons 85 62 .578 1 Terry Collins Pittsburgh Pirates
Louisville Redbirds 74 72 .507 11½ Mike Jorgensen St. Louis Cardinals
Indianapolis Indians 61 85 .418 24½ Tim Johnson Montreal Expos
West Division W L Pct. GB Manager Affiliation
Omaha Royals 86 60 .589 -- Sal Rende Kansas City Royals
Iowa Cubs 72 74 .493 14 Jim Essian Chicago Cubs
Denver Zephyrs 68 78 .466 18 Dave Machemer Milwaukee Brewers
Oklahoma City 89ers 58 87 .400 27½ Steve Smith Texas Rangers

Championship Finals[edit]

Omaha vs. Nashville
Date Away Home
September 4 Nashville 0 Omaha 1
September 5 Nashville 5 Omaha 3
September 6 Omaha 8 Nashville 7
20 innings
September 7 Omaha 4 Nashville 5
September 8 Omaha 8 Nashville 7
Omaha wins series 3-2 and
advances to Triple-A Classic

League Leaders[edit]

Batting[edit]

Pitching[edit]

  • Wins Chris Hammond, Nashville, 15
  • Earned Run Average Hammond, 2.17
  • Complete Games Scott Anderson, Indianapolis, 6
  • Shutouts Hammond, 3
  • Strikeouts Hammond, 144
  • Saves Mike Perez, Louisville, 31

All-Star Team[edit]

References[edit]

The Encyclopedia of Minor League Baseball. W. Lloyd Johnson and Miles Wolff, editors. Baseball America, 1993.

1991 Baseball Almanac

External Links[edit]

1990 AA - The Baseball Cube