Talk:1991 Caribbean Series

From BR Bullpen

How did Licey only play five games while Lara played seven, with Santurce and Tijuana playing four.

According to the text there was a three-game round-robin (one-game vs each team) followed a best-of-three finals that lasted two games. The most logical series format would be:

  • Round Robin
    1. Licey: 3-0
    2. Lara: 1-2
    3. Santurce or Tijuana: 0-3 (loser of round 2)?
    4. Santurce or Tijuana: 0-3 (loser of round 1)
  • Playoffs
ROUND 1    ROUND 2       ROUND 3
=================================================
                       Licey**** W W
        Santurce/              ****** LICEY CHAMP
          Tijuana---|L         |
                    ************
Lara*******W        *
          ***********
Santurce/ |
Tijuana  -|
  • Playoffs
    1. Licey: 2-0
    2. Lara: 2-2
    3. Santurce: 0-1
    4. Tijuana: 0-1

Does anyone know if this is true (or what he proper format was)? --MichaelEng (talk) 09:02, 8 November 2006 (EST)

Here's what happened. In the round-robin, Licey beat everybody once. Lara, Santurce and Tijuana split their games with one another. So, it was

Licey 3-0 Tijuana 1-2 Lara 1-2 Santurce 1-2

Lara then beat Santurce and Tijuana once each in a playoff to make it to the finals against Licey.

I'll clarify things in the article - --Mischa 16:35, 10 November 2006 (EST)